Dividing by 11

Tuesday, January 12, 2010



    Let's look at 352, which is divisible by 11; the answer is 32. 3+2 is 5; another way to say this is that 35 -2 is 33. Now look at 3531, which is also divisible by 11. It is not a coincidence that 353-1 is 352 and 11 × 321 is 3531. Here is a generalization of this system. Let's look at the number 94186565. First we want to find whether it is divisible by 11, but on the way we are going to save the numbers that we use: in every step we will subtract the last digit from the other digits, then save the subtracted amount in order. Start with
    9418656 - 5 = 9418651     SAVE 5
         Then 941865  - 1 = 941864      SAVE 1
         Then 94186   - 4 = 94182       SAVE 4
         Then 9418    - 2 = 9416        SAVE 2
         Then 941     - 6 = 935         SAVE 6
         Then 93      - 5 = 88          SAVE 5
         Then 8       - 8 = 0           SAVE 8
    Now write the numbers we saved in reverse order, and we have 8562415, which multiplied by 11 is 94186565.

    Here's an even easier method, contributed by Chis Foren: Take any number, such as 365167484. Add the first, third, fifth, seventh,.., digits.....3 + 5 + 6 + 4 + 4 = 22 Add the second, fourth, sixth, eighth,.., digits.....6 + 1 + 7 + 8 = 22 If the difference, including 0, is divisible by 11, then so is the number. 22 - 22 = 0 so 365167484 is evenly divisible by 11.

Dividing by 8

    Check the last three digits. Since 1000 is divisible by 8, if the last three digits of a number are divisible by 8, then so is the whole number. Example: 33333888 is divisible by 8; 33333886 isn't. How can you tell whether the last three digits are divisible by 8? Phillip McReynolds answers: If the first digit is even, the number is divisible by 8 if the last two digits are. If the first digit is odd, subtract 4 from the last two digits; the number will be divisible by 8 if the resulting last two digits are. So, to continue the last example, 33333888 is divisible by 8 because the digit in the hundreds place is an even number, and the last two digits are 88, which is divisible by 8. 33333886 is not divisible by 8 because the digit in the hundreds place is an even number, but the last two digits are 86, which is not divisible by 8.
    Sara Heikali explains this test of divisibility by eight for numbers with three or more digits:
    1. Write down the units digit of the original number.
    2. Take the other numbers to the left of the last digit,
    and multiply them by two.
    3. Add the answer from step two to the number from step one.
    4. If the sum from step three is divisible by eight, then the 
    original number is divisible by eight, as well. If the sum is 
    not divisible by eight, then the original number is not 
    divisible by eight.
    
    For example, if the number we are testing is 104, then
    1. Write down just the digits in ones place: 4.
    2. Take the other numbers to the left of that last digit,
    and multiply them by two: 10 × 2 = 20.
    3. Add the answer from step two to the number from step one:
    4 + 20 = 24.
    4. Twenty-four is divisible be eight. Therefore, our original
    number, one hundred and four, is also divisible by eight.
    

Dividing by 7

To find out if a number is divisible by seven, take the last digit, double it, and subtract it from the rest of the number.
Example: If you had 203, you would double the last digit to get six, and subtract that from 20 to get 14. If you get an answer divisible by 7 (including zero), then the original number is divisible by seven. If you don't know the new number's divisibility, you can apply the rule again. 
Matthew Correnti describes this method:
If you do not know if a two-digit number, call it ab, is divisible 
by 7, calculate 2a + 3b. This will yield a smaller number, and if 
you do the process enough times you will eventually -- if the 
number ab is divisible by 7 -- end up with 7.

You can use a similar method if you have a three-digit number abc: 
take the digit a and multiply it by 2, then add it to the number bc, 
giving you 2a + bc; repeat and reduce until you recognize the 
result's divisibility by seven. With a four-digit number abcd, take 
the digit a and multiply by 6, then add 6a to bcd giving. This 
usually gives you a three-digit number; call it xyz. Take that x 
and, as described previously, multiply x by two and add to yz 
(i.e., 2x + yz). Again, repeat and reduce until you recognize the 
result's divisibility by seven.
    Another visitor observes:
    Here is one formula for seven...
    
    3X + L
    
    L = last digit
    X = everything in front of last digit.
    
    All numbers that are divisible by seven have this in common. 
    There are no exceptions.
    
    For example, 42: 3(4) + 2 = 14.
    Seven divides into 14, so it divides into 42.
    
    Next example, 105: 3(10) + 5 = 35.
    Seven divides into 35, so it divides into 105.
    
    Here is another formula for seven:
    
    4X - L
    
    When using this formula, if you get zero, seven or a multiple of seven, 
    the number will be divisible by seven.
    
    For example, 56: 4(5) - 6 = 14.
    Seven divides into 14, so it divides into 56.
    
    Next example, 168: 16(4) - 8 = 56.
    Seven divides into 56, so it divides into 168.
    
    Similarly:
    
    The formula for 2 is 2X + L
    The formula for 3 is 4X + L
    The formula for 4 is 6X + L
    The formula for 5 is 5X + L
    The formula for 6 is 2X + L and 4X + L -- in other words, the formulas for 2 and 3
                                              must work before the number is divisible by 6.
    The formula for 9 is X + L
    The formula for 11 is X - L
    The formula for 12 is 2X - L
    The formula for 13 is 3X - L
    The formula for 14 is 4X - L and 2X + L -- in other words, the formulas for 7 and 2 
                                               must work before the number is divisible by 14.
    The formula for 17 is 7X - L
    The formula for 21 is X - 2L
    The formula for 23 is 3X - 2L
    The formula for 31 is X - 3L
    

    Sara Heikali explains this way to test a number with three or more digits for divisibility by seven:
    1. Write down just the digits in the tens and ones places.
    2. Take the other numbers to the left of those last two digits, 
    and multiply them by two.
    3. Add the answer from step two to the number from step one.
    4. If the sum from step three is divisible by seven, then the 
    original number is divisible by seven, as well. If the sum is 
    not divisible by seven, then the original number is not 
    divisible by seven.
    
    For example, if the number we are testing is 112, then
    1. Write down just the digits in the tens and ones places: 12.
    2. Take the other numbers to the left of those last two digits, 
    and multiply them by two: 1 × 2 = 2.
    3. Add the answer from step two to the number from step one: 
    12 + 2 = 14.
    4. Fourteen is divisible be seven. Therefore, our original 
    number, one hundred twelve, is also divisible by seven.
    

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